b^2-7b-14=0

Solution for b^2-7b-14=0 equation:

b^2-7b-14=0

a = 1; b = -7; c = -14;
Δ = b2-4ac
Δ = -72-4·1·(-14)
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{105}}{2*1}=\frac{7-\sqrt{105}}{2}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{105}}{2*1}=\frac{7+\sqrt{105}}{2}
$